日常工作中,会遇到一堆目录,如何查看各目录大小呢,大家都知道du命令
先列出前10条
root@local /scripts]#du -sh * | head120K 2017031510248K 201703151423M 2017031515664K 2017031516656K 20170315172.0M 201703151868K 2017031519884K 2017031520580K 201703152160K 2017031609
再排序
root@local /scripts]#du -sh * | sort -nr | head1020K 20170621201008K 20170330161000K 2017032221988K 2017052420988K 2017033118988K 201703191298K 201703281080K 201705111476M 201705091868K 2017052010
是不是乱了?这是du命令中-h导致的,先计算了大小,但是在排序的时候,只针对数字,不会识别后面的K 和 M ,优化下
root@local /scripts]#du -s * | sort -nr | head | awk '{printf"%sM\n",$1/1024 }'125.906M66.4023M65.8516M63.5117M53.5859M53.125M51.4805M47.8945M46.8867M44.25M
OK了